Q. A liquid flows through a pipe of non-uniform cross-section. If $A_{1}$ and $A_{2}$ are the cross-sectional area of the pipe at two points, the ratio of velocities of the liquid at these points will be
A) $A_{1}A_{2}$
B) $\frac{A_{1}}{A_{2}}$
C) $\frac{A_{2}}{A_{1}}$
D) $\frac{1}{{A_{1}A}_{2}}$
Explanation
(c) Volume of liquid flowing at first point $= A_{1}v_{1}$.
Similarly, volume of liquid flowing at second point $= A_{2}v_{2}$
From equation of continuity,
$A_{1}v_{1} = A_{2}v_{2}$
$or\ \ \ \frac{v_{1}}{v_{2}} = \frac{A_{2}}{A_{1}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.