Q.
A liquid X of density 3.36 g ${cm}^{- 3}$ is poured in a U-tube, which contains Hg. Another liquid Y is poured in left arm with height 8 cm, upper levels of X and Y are same. What is density of Y?
A) $0.8\ {gcc}^{- 1}$
B) $1.2\ {gcc}^{- 1}$
C) $1.4\ {gcc}^{- 1}$
D) $1.6{gcc}^{- 1}$
Explanation
(a) As shown in figure, in the two arms of a tube pressure remains same on surface PP’.
[image:10_image73.emf]
Hence, $8 \times \rho_{y} \times g \times 2 \times \rho_{Hg} \times g = 10 \times \rho_{x} \times g$
$\therefore$ $8\rho_{y} + 2 \times 113.6 = 10 \times 3.36$
or $\rho_{y} = \frac{36.6 - 27.2}{8} = 0.8\ g\ cc^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.