Explanation

(a) Excess pressure is given by $p = \frac{4T}{r}$
$\Longrightarrow \ \ \ r = \frac{4T}{p}$
$\therefore\ \ \ \ \ \ \frac{r_{1}}{r_{2}} = \frac{p_{2}}{p_{1}} = \frac{1.02}{1.01} = \frac{102}{101}$
$Ratio\ of\ {volume}^{'}s = \frac{\frac{4}{3}\pi r_{1}^{3}}{\frac{4}{3}\pi r_{2}^{3}} = \frac{(102)^{3}}{(101)^{3}} \approx 2$