Q.
Figure shows the vertical cross section of a vessel filled with a liquid of density$\rho$. The normal thrust per unit area on the walls of the vessel at point $P$, as shown will be
A) $h\ \rho\ g$
B) $H\ \rho\ g$
C) $(H - h)\rho\ g$
D) $(H - h)\rho\ g\cos\theta$
Explanation
(c) Depth of $p$ below the free surface of water in the vessel$= (1 + h)$. Since the liquid exerts equal pressure in all direction at one level, hence the pressure at $p = (H - h)\ \rho\ g$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.