Q. A hole is made at the bottom of the tank filled with water (density 1000 kg/$m^{3}$). If the total pressure at the bottom of tank is 3 atm (1 atm = $10^{5}\ {N/m}^{2}$), then the velocity of efflux is
A) $\sqrt{200}$ m/s
B) $\sqrt{400}$ m/s
C) $\sqrt{500}$ m/s
D) $\sqrt{800}$ m/s
Explanation
(b) [image:10_image75.jpeg]
Apply Bernoullis, theorem
$p_{1} + 0\rho gH = p_{2 +}\frac{1}{2}{\rho v}^{2} + \rho gH$
$p_{1} - p_{2} = \frac{1}{2}{\rho v}^{2}$
$3 \times 10^{5} - 1 \times 10^{5} = \frac{1}{2}\rho v^{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ $
$2 \times 10^{5} = \frac{1}{2}\rho v^{2}$
$2 \times 10^{5} = \frac{1}{2} \times 10^{3} \times v^{2}$
$v^{2} = 400$
$v = \sqrt{400}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.