Explanation

(d) Let the volume of iceberg inside sea is $x,$ then
$\frac{Volume\ of\ iceberg\ inside\ sea}{Total\ volume\ of\ iceberg} = \frac{Density\ of\ ice}{Density\ of\ sea\ water}$
$or\ \ \ \frac{x}{V} = \frac{0.92}{1.03}$
$\ \ so\ \ \ \ x = \frac{0.92}{1.03}V$
Percentage of total volume of iceberg above the level of sea water is
$= \left( \frac{V - x}{V} \right) \times 100$
$= \left( \frac{V - \left( \frac{0.92}{1.03} \right)V}{V} \right) \times 100\%$
$= \frac{0.11}{1.03} \times 100\% = 11\%\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (nearly)$