Q.
The diagram shows three soap bubbles $A,\ B$ and $C$ prepared by blowing the capillary tube fitted with stop cocks $S,\ S_{1},\ S_{2}$ and$S_{3}$. With stop cock $S$ closed and stop cocks $S_{1},\ S_{2}$ and$S_{3}$. Opened
A) $B$ will start collapsing with volumes of $A$ and $C$ increasing
B) $C$ will start collapsing with volume of $A$ and $B$ increasing
C) Volume of $A,\ B$ and $C$ will become equal in equilibrium
D) $C$ and $A$ will both start collapsing with volume of $B$ increasing
Explanation
(b) As excess pressure,$p \propto 1/r$, therefore, pressure inside $C$ is highest and pressure inside $B$ is lowest. The pressure inside $A$ is in between. Therefore $C$ starts collapsing with volume of $A$ and $B$ increasing
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.