Q. The pressure on a swimmer 20 m below the surface of water at sea level is
A) 1.0 atm
B) 2.0 atm
C) 2.5 atm
D) 3.0 atm
Explanation
(d) Pressure at depth $h = p_{a} + \rho gh$
where $p_{a}$ is atmospheric pressure
$\ = 1.01 \times 10^{5}\ {Nm}^{2}$
$\therefore$ $p_{total} = 1.01{\times 10}^{5} + 10^{3} \times 10 \times 20$
$\ \ \ = 3.01 \times 10^{5}\ Pa = 3\ atm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.