Q. A container with square base of side $a$ hight $H$ with a liquid. A hole is made at a depth $h$ from the free surface of water. With what acceleration the container must be accelerated, so that the water does not come out?
A) G
B) $\frac{g}{2}$
C) $\frac{2gH}{2}$
D) $\frac{2gh}{a}$
Explanation
(d) Bernoulli’s theorem is a form of conversion of energy, hence we have
$H_{0} + h\rho g = H_{0} + \frac{1}{2}\rho v^{2}\ \ \ \ \ \ $
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When vessel is accelerated down with an acceleration g (free fall), then pseudo acceleration g will act vertically upwards and effective value of g is zero. Hence, water will not flow.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.