(b) Let $A$ be the area of cross-section of through and $\rho$ be the density of mercury
Initial mass of mercury in trough
$= A \times 3.6 \times \rho$
Final mass of mercury in trough
$= A\ h^{'}\rho = (A \times 3.6 \times \rho) \times 2$
or $h^{'} = 7.2$ cm