Q. A sphere of radius $R$ is gently dropped into liquid of viscosity ɳ in a vertical uniform tube. It attains a terminal velocity $v$. Another sphere of radius $2R$ when dropped into the same liquid, will attains its terminal velocity

A) $v$
B) $2v$
C) $4v$
D) $9v$
Explanation

(c) Terminal velocity
$v \propto r^{2}$
$\therefore\ \ \frac{v^{'}}{v} = \frac{(2R)^{2}}{(R)^{2}}$
$or\ \ v^{'} = 4v$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.