Q. There are two holes one each along the opposite sides of a wide rectangular tank. The cross-section of each hole is 0.01$m^{2}$ and the vertical distance between the holes is one meter. The tank is filled with water flows out of the holes is (density of water$= 1000\ kgm^{- 3})$
A) 100
B) 200
C) 300
D) 400
Explanation
(b) The net force on the tank
$F = 2A\rho gh$
Where $A = area\ of\ cross - section\ of\ the\ hole$
$\rho =$ density of water
$h = \ $vertical distance between the holes
$\therefore$ $F = 2 \times 0.01 \times 1000 \times 10 \times 1 = 200N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.