Q. A rain drop of radius 1.5 mm, experiences a drag force $F = (2 \times 10^{- 5}\ v)$ N, while falling through air from a height 2 km, with a velocity$v$. The terminal velocity of the rain drop will be nearly (use $g = 10\ ms^{- 2}$)

A) $200\ ms^{- 1}$
B) $80\ ms^{- 1}$
C) $7\ ms^{- 1}$
D) $3\ ms^{- 1}$
Explanation

(c) When terminal velocity $v$ is reaching, then
$F = 2 \times 10^{- 5}v = \frac{4}{3}\pi\ r^{3}\rho g$
$2 \times 10^{- 5}v = \frac{4}{3} \times \frac{22}{7} \times \left( 1.5 \times 10^{- 3} \right)^{3} \times 10^{3} \times 10$
On solving, $v = 7.07ms^{- 1} \approx 7ms^{- 1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.