Q.
In the figure, the velocity $V_{3}$ will be
A) Zero
B) $4ms^{- 1}$
C) $1ms^{- 1}$
D) $3ms^{- 1}$
Explanation
(c) According to equation of continuity
$A_{1}V_{1} = A_{2}V_{2} + A_{3}V_{3}$
$\Rightarrow 4 \times 0.2 = 2 \times 0.2 + 0.4 \times V_{3} \Rightarrow V_{3} = 1m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.