Q. A piece of wax weighs 18.03 g in air. A piece of metal is found to weigh 17.03 g in water. It is tied to the wax and both together weigh 15.23 g in water. Then, the specific gravity of wax id
A) $\frac{18.03}{17.03}$
B) $\frac{17.03}{18.03}$
C) $\frac{18.03}{19.83}$
D) $\frac{15.03}{17.03}$
Explanation
(c) Weight of wax in air,
$W_{a} = 18.03\ g$
Weight of metal piece in water$= 17.03\ g$
Weight of metal piece and wax in water $= 15.23\ g$
Weight of wax in water
$W_{w} = 15.23 - 17.03 = - 1.8g$
Therefore, specific gravity of wax
$= \frac{weigth\ of\ wax\ in\ air\ }{weight\ of\ wax\ in\ air - weight\ of\ wax\ in\ water}$
$= \frac{18.03}{18.03 - ( - 1.8)} = \frac{18.03}{19.83}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.