Q. The terminal velocity of spherical ball of radius $a$ falling through a viscous liquid is proportional to
A) $a$
B) $a^{2}$
C) $a^{3}$
D) $a^{- 1}$
Explanation
(b) If spherical body of radius a is dropped in a viscous fluid, it is first accelerated and then its acceleration becomes zero and it attains a constant velocity called terminal velocity.
$Terminal\ velocity,\ \ v = \frac{2}{9}\ \frac{a^{2}(\rho - \sigma)g}{ɳ}$
where $\rho$ is the density of the body,$\sigma$ is the density of fluid and ɳ is coefficient of viscosity.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.