Two substances of densities $\rho_{1}$ and $\rho_{2}$ are mixed in equal volume and the relative density of mixture is 4. When they are mixed in equal masses, the relative density of the mixture is 3. The values of $\rho_{1}$ and $\rho_{2}$ are

Question

Dr. Abubacker · Accepted Answer

(a) When substances are mixed in equal volume then density
$= \frac{\rho_{1} + \rho_{2}}{2} = 4 \Rightarrow \rho_{1} + \rho_{2} = 8$ …(i)
When substances are mixed in equal masses the density
$= \frac{2\rho_{1}\rho_{2}}{\rho_{1} + \rho_{2}} = 3$
$\Rightarrow 2\rho_{1}\rho_{2} = 3(\rho_{1} + \rho_{2})$ …(ii)
By solving (i) and (ii) we get $\rho_{1} = 6$ and $\rho_{2} = 2$

Q. Two substances of densities $\rho_{1}$ and $\rho_{2}$ are mixed in equal volume and the relative density of mixture is 4. When they are mixed in equal masses, the relative density of the mixture is 3. The values of $\rho_{1}$ and $\rho_{2}$ are

Explanation

Reviewed by Dr. Abubacker

Want more practice?