(c) Surface energy = surface tension $\times$ surface area
$E = S \times 2A$
New surface energy, $E_{1} = S \times 2(A/2) = S \times A$
% decrease in surface energy $= \frac{E - E_{1}}{E} \times 100$
$= \frac{2\ SA - SA}{2\ SA} \times 100 = 50\%$