Q. If the atmospheric pressure is $P_{a}$, then the pressure $P$ at depth $h$ below the surface of a liquid of density $\rho$ open to the atmosphere is
A) $P_{a} - \frac{\rho gh}{2}$
B) $P_{a} - \rho gh$
C) $P_{a}$
D) $P_{a} + \rho gh$
Explanation
(d) $P = P_{a} + \rho gh$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.