A layer of glycerine of thickness 1 mm is present between a large surface area and a surface area of $0.1\ m^{2}$. With what force the small surface is to be pulled, so that it can move with a velocity of $1\ {ms}^{- 1}$? (Given that coefficient of viscosity = $0.07\ kg\ m^{- 1}\ s^{- 1}$)

Question

Dr. Abubacker · Accepted Answer

(b) $ɳ = 0.07\ kg\ m^{- 1}s^{- 1},\ dv = 1\ {ms}^{- 1},$
$dx = 1\ mm = 1 	imes 10^{- 3}\ m,\ \ \ A = 0.1m^{2}$
$	herefore\ F = ɳA\frac{dv}{dx}$
$= 0.07 	imes 0.1 	imes \frac{1}{1 	imes 10^{- 3}} = 7N$

Q. A layer of glycerine of thickness 1 mm is present between a large surface area and a surface area of $0.1\ m^{2}$. With what force the small surface is to be pulled, so that it can move with a velocity of $1\ {ms}^{- 1}$? (Given that coefficient of viscosity = $0.07\ kg\ m^{- 1}\ s^{- 1}$)

Explanation

Reviewed by Dr. Abubacker

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