Q. The level of water in a tank is 5 m high. A hole of area $10\ cm^{2}$ is made in the bottom of the tank. The rate of leakage of water from the hole is
A) $10^{- 2}m^{3}s^{- 1}$
B) $10^{2}m^{3}s^{- 1}$
C) $10\ m^{3}s^{- 1}$
D) $10^{- 2}m^{- 3}s^{- 1}$
Explanation
(a) Velocity of efflux, $v = \sqrt{2\ gh}$;
Volume of liquid flowing out per sec
$= v \times A = \sqrt{2\ gh} \times A$
$= \sqrt{2 \times 10 \times 5} \times \left( 10 \times 10^{- 4} \right) = 10^{- 2}m^{3}s^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.