Q. A liquid flows in a tube from left to right as shown in figure $A_{1}$ and $A_{2}$ are the cross-sections of the portions of the tube as shown. Then the ratio of speeds $v_{1}/v_{2}$ will be
A) $A_{1}/A_{2}$
B) $A_{2}/A_{1}$
C) $\sqrt{A_{2}}/\sqrt{A_{1}}$
D) $\sqrt{A_{1}}/\sqrt{A_{2}}$
Explanation
The correct answer is Option B: $A_{2}/A_{1}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.