Q.
A jar shown in figure is filled with a liquid of density $\rho$. The jar is placed in vacuum. Cross-section of the jar is circular and base is having a radius $R$. The force exerted by the liquid column on the base of the jar is
A) $\rho\ g(a + b + c)\pi R^{2}$
B) Less than $\rho\ g(a + b + c)\pi R^{2}$
C) Greater than $\rho\ g(a + b + c)\pi R^{2}$
D) $2\rho\ g(a + b + c)\pi R^{2}$
Explanation
(c) When jar is placed in vacuum, the liquid level rises up to the top of jar. The force exerted by liquid on the base of jar = force due to vertical column of liquid of height $(a + b + c)$+ vertical downward
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Component of thrust $F$ acting on the portion $BC$ of jar
$= (a + b + c)\rho g \times \pi R^{2} + F\sin{60{^\circ}}$
$=$ greater than $(a + b + c)\rho g \times \pi R^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.