Q. A hole in the bottom of the tank having water. If total pressure at bottom is 3 atm ($1$ $atm\ = 10^{5}\ Nm^{- 2}$), then velocity of water flowing from hole is
A) $\sqrt{400}\ ms^{- 1}$
B) $\sqrt{600}\ ms^{- 1}$
C) $\sqrt{60}\ ms^{- 1}$
D) None of these
Explanation
(a) Total pressure $(p)$= atmospheric pressure $(p_{0})$ + pressure due to water column in tank $(p')$
$\therefore p^{'} = p - p_{0} = 3 - 1 = 2$ atmophere
Or $h \times 10^{3} \times 10 = 2 \times 10^{5}$ or $h = 20$ m
$v = \sqrt{2gh} = \sqrt{2 \times 10 \times 20} = \sqrt{400\ }\ ms^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.