Q. A $10\ {cm}^{3}$ cube floats in water with a height of $4\ {cm}^{3}$ remaining above the surface. The density of the material form which the cube is made is
A) $0.6\ g\ {cm}^{- 3}$
B) $1.0\ g\ {cm}^{- 3}$
C) $0.4\ g\ {cm}^{- 3}$
D) $0.24\ g\ {cm}^{- 3}$
Explanation
(a) $\frac{Volume\ of\ cube\ submerged\ }{Total\ volume} = \frac{Density\ of\ cube\ material}{Density\ of\ water}$
$\Longrightarrow \ \ \ \ \frac{10 - 4}{10} = \frac{d}{1}$
$\therefore\ \ \ d = \frac{6}{10} = 0.6\ g\ {cm}^{- 3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.