Explanation

(a) Applying continuity equation at1 and2, we have
$A_{1}v_{1} = A_{2}v_{2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ldots\ldots\ldots(i)}$
Further applying Bernoulli’s equation at these two points, we have
$p_{0} + \rho gh + \frac{1}{2}\rho v_{1}^{2} = p_{0} + 0 + \frac{1}{2}\rho v_{2}^{2\ \ }\ \ldots\ldots(ii)$
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Solving Eqs. (i) and (ii) we have
$v_{2}^{2} = \frac{2gh}{1 - \frac{A_{2}^{2}}{A_{1}^{2}}}$
Substituting the values, we have
$v_{2}^{2} = \frac{2 \times 10 \times 2.475}{1 - {(0.1)}^{2}} = 50m^{2}s^{- 2}$