Q. A tank is filled with water upto a height$H$. Water is allowed to come out of a hole $P$ in one of the walls at a depth $h$ below the surface of water (see figure). Express the horizontal distance $X$ in terms of $H$ and $h$

A) $X = \sqrt{h(H - h)}$
B) $X = \sqrt{\frac{h}{2}(H - h)}$
C) $X = 2\sqrt{h(H - h)}$
D) $X = 4\sqrt{(H - h)}$
Explanation

(c) Vertical distance covered by water before striking ground$= (H - h)$. Time taken is, $t = \sqrt{2(H - h)g}$; Horizontal velocity of water coming out of hole at $P,\ u = \sqrt{2gh}$
$\therefore$ Horizontal range
$= ut = \sqrt{2gh} = \sqrt{2(H - g)/g}$
$= 2\sqrt{h(H - h)}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.