Q. A block of steel of size $5\ cm \times 5\ cm \times 5\ cm$ is weighed in water. If the relative density of steel is 7, its apparent weight is
A) $6 \times 5 \times 5 \times 5\ gf$
B) $4 \times 4 \times 4 \times 7\ gf$
C) $5 \times 5 \times 5 \times 7\ gf$
D) $4 \times 4 \times 4 \times 6\ gf$
Explanation
(a) Apparent weight $= V(\rho - \sigma)g$
$= 5 \times 5 \times 5(7 - 1)g = 6 \times 5 \times 5 \times 5\ gf$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.