Q. Two water pipes $P$ and $Q$ having diameter $2 \times 10^{- 2}$ m and $4 \times 10^{- 2}$ m respectively are joined in series with the main supply line of water. The velocity f water flowing in pipe $P$ is

A) 4 times that of Q
B) 2 times that of Q
C) 1/2 times that of Q
D) 1/4 times that of Q
Explanation

(a) Using theorem of continuity, we have
$\pi D_{p}^{2}v_{p} = \pi D_{Q}^{2}v_{Q};$
$v_{p} = \left( \frac{D_{Q}}{D_{P}} \right)^{2}v_{Q} = \left( \frac{4 \times 10^{- 2}}{2 \times 10^{- 2}} \right)^{2} \times v_{Q} = v_{Q} = 4v_{Q}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.