Q. A siphon in use is demonstrated in the following figure. The density of the liquid flowing in siphon is $1.5\ gm/cc$. The pressure difference between the point $P$ and $S$ will be
A) $10^{5}\ N/m$
B) $2 \times 10^{5}N/m$
C) Zero
D) Infinity
Explanation
(c) As the both points are at the surface of liquid and these points are in the open atmosphere. So both point possess similar pressure and equal to $1\ atm$. Hence the pressure difference will be zero
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.