(c) Gravitational force remains constant on the falling spherical ball. It is represented by straight line$P$. The viscous force $(F = 6\pi\eta rv)$ increases as the velocity increases with time. Hence, it is represented by curve$Q$. Net force = gravitational force $–$ viscous force. As viscous force increases, net force decreases and finally becomes zero. Then the body falls with a constant terminal velocity. It is thus represented by curve $R$