Q. A vessel of area of cross-section $A$ has liquid to a height $H$. There is a hole at the bottom of vessel having area of cross-section $a$. The time taken to decrease the level from $H_{1}$ to $H_{2}$ will be
A) $\frac{A}{a}\sqrt{\frac{2}{g}}\lbrack\sqrt{H_{1}} - \sqrt{H_{2}}\rbrack$
B) $\sqrt{2gh}$
C) $\sqrt{2gh(H_{1} - H_{2})}$
D) $\frac{A}{a}\sqrt{\frac{g}{2}}\lbrack\sqrt{H_{1}} - \sqrt{H_{2}}\rbrack$
Explanation
The correct answer is Option A: $\frac{A}{a}\sqrt{\frac{2}{g}}\lbrack\sqrt{H_{1}} - \sqrt{H_{2}}\rbrack$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.