Q. The terminal velocity $v$ of a spherical ball of lead of radius $R$ falling through a viscous liquid varies with $R$ such that
A) $\frac{v}{R} =$ constant
B) $vR =$ constant
C) $v =$ constant
D) $\frac{v}{R^{2}} =$ constant
Explanation
(d) Terminal velocity, $v = \frac{2r^{2}(\rho - \rho_{0})g}{9\eta}$
Or $\frac{v}{r^{2}} = \frac{2(\rho - \rho_{0})g}{9\eta} =$ constant
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.