Q. Two soap bubbles of radii $r_{1}$ and $r_{2}$ equal to 4 cm and 5 cm respectively are touching each other over a common surface $AB$ (shown in figure). Its radius will be

A) 4 cm
B) 4.5 cm
C) 5 cm
D) 20 cm
Explanation

(d) $\frac{4S}{r_{1}} - \frac{4S}{r_{2}} = \frac{4S}{r}$
Or $\frac{1}{r} = \frac{1}{r_{1}} - \frac{1}{r_{2}} = \frac{1}{4} - \frac{1}{5} = \frac{1}{20}$ or $r = 20$ cm

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.