Water flows in a streamlined manner through a capillary tube of radius $a$, the pressure difference being $P$ and the rate of flow $Q$. If the radius is reduced to $a/2$ and the pressure increased to $2P$, the rate of flow becomes

Question

Dr. Abubacker · Accepted Answer

(d) $V = \frac{\pi{pr}^{4}}{8\eta l}\ 	herefore V \propto P\ r^{4}\ \ \ \lbrack\eta$ and $l$ are connected]
$	herefore\frac{V_{2}}{V_{1}} = \left( \frac{P_{2}}{P_{1}} ight)\left( \frac{r_{2}}{r_{1}} ight)^{4} = 2 	imes \left( \frac{1}{2} ight)^{4} = \frac{1}{8}\ 	herefore V_{2} = \frac{Q}{8}$

Q. Water flows in a streamlined manner through a capillary tube of radius $a$, the pressure difference being $P$ and the rate of flow $Q$. If the radius is reduced to $a/2$ and the pressure increased to $2P$, the rate of flow becomes

Explanation

Reviewed by Dr. Abubacker

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