Two identical bodies have temperatures 277$℃$ and 67$℃$ . If the surroundings temperature is 27$℃$, the ratio of loss of heats of the two bodies during the same interval of time is(approximately)

Question

Dr. Abubacker · Accepted Answer

(d) $T_{1} = 277℃ = 277 + 273 = 550\ K$
$T_{2} = 67℃ = 67 + 273 = 340\ K$
Temperature of surrounding
$T = 27℃ = 27 + 273 = 300\ K$
Ratio of loss of heat=$\frac{T_{1}^{4} - T^{4}}{T_{2}^{4} - T^{4}}$
$= \frac{\left( \frac{T_{1}}{T} \right)^{4} - 1}{\left( \frac{T_{2}}{T} \right)^{4} - 1} = \frac{\left( \frac{550}{300} \right)^{4} - 1}{\left( \frac{340}{300} \right)^{4} - 1} = \frac{9.5}{0.5} = \frac{19}{1}$

Q. Two identical bodies have temperatures 277$℃$ and 67$℃$ . If the surroundings temperature is 27$℃$, the ratio of loss of heats of the two bodies during the same interval of time is(approximately)

Explanation

Reviewed by Dr. Abubacker

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