If temperature of a black body increases from $7℃$ to $287℃$, then the rate of energy radiation increases by

Question

Dr. Abubacker · Accepted Answer

(b) For a black body rate of energy $\frac{Q}{t} = P = A\sigma T^{4}$
$\Rightarrow P \propto T^{4} \Rightarrow \frac{P_{1}}{P_{2}} = \left( \frac{T_{1}}{T_{2}} \right)^{4} = \left\{ \frac{(273 + 7)}{(273 + 287)} \right\}^{4} = \frac{1}{16}$

Q. If temperature of a black body increases from $7℃$ to $287℃$, then the rate of energy radiation increases by

Explanation

Reviewed by Dr. Abubacker

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