Q. The temperature of two bodies $A$ and $B$ are $727℃$ and $127℃$. The ratio of rate of emission of radiations will be

A) 727/127
B) 625/16
C) 1000/400
D) 100/16
Explanation

(b) $\frac{E_{1}}{E_{2}} = \left( \frac{T_{1}}{T_{2}} \right)^{4} = \left( \frac{727 + 273}{127 + 273} \right)^{4} = \frac{(1000)^{4}}{(400)^{4}} = \frac{10^{4}}{4^{4}} = \frac{625}{16}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.