The wavelength of maximum energy, released during an atomic explosion was $2.93 imes 10^{- 10}m$. Given that the Wien’s constant is $2.93 imes 10^{- 3}\ m - K$, the maximum temperature attained must be of the order of

Question

The wavelength of maximum energy, released during an atomic explosion was $2.93 	imes 10^{- 10}m$. Given that the Wien’s constant is $2.93 	imes 10^{- 3}\ m - K$, the maximum temperature attained must be of the order of

Dr. Abubacker · Accepted Answer

(b) Wien’s displacement law is given by
$\lambda_{m}T = constant$ (say $b$)
Given, b=Wien’s constant=$2.93 	imes 10^{- 3}\ m - K$
$\lambda_{m} = 2.93 	imes 10^{- 10}m$
Substituting the values, we obtain
$T = \frac{b}{\lambda_{m}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \  = \frac{2.93 	imes 10^{- 3}}{2.93 	imes 10^{- 10}} = 10^{7}\ K$

Q. The wavelength of maximum energy, released during an atomic explosion was $2.93 \times 10^{- 10}m$. Given that the Wien’s constant is $2.93 \times 10^{- 3}\ m - K$, the maximum temperature attained must be of the order of

Explanation

Reviewed by Dr. Abubacker

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