Q. A conductor of area of cross-section 100${\ cm}^{2}$ and length 1 cm has coefficient of thermal conductivity 0.76${cals}^{- 1}m^{- 1}K^{- 1}$. If 30 cal of heat flows through the conductor per second. Find the temperature difference across the conductor.

A) 40$℃$
B) 20$℃$
C) 25$℃$
D) 35$℃$
Explanation

(a) Heat current $H = \frac{KA\mathrm{\Delta}\theta}{l}$
$\therefore$ $\mathrm{\Delta}\theta = \frac{Hl}{KA}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{30 \times 1 \times 10^{- 2}}{0.76 \times 100 \times 10^{- 4}} = 39.47$
$= 40℃(approx.)$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.