Q. The initial temperature of a body is $80℃$. If its temperature falls to $64℃$ in $5\ minutes$ and in $10\ minutes$ to $52℃$ then the temperature of surrounding will be

A) $26℃$
B) $49℃$
C) $35℃$
D) $42℃$
Explanation

(b) According to Newton’s law $\frac{\theta_{1} - \theta_{2}}{t} = k\left\lbrack \frac{\theta_{1} + \theta_{2}}{2} - \theta_{0} \right\rbrack$
Initially,
$\frac{(80 - 64)}{5} = K\left( \frac{80 + 64}{2} - \theta_{0} \right) \Rightarrow 3.2 = K(72 - \theta_{0})\ \ ...(i)$
Finally
$\frac{(64 - 52)}{10} = K\left\lbrack \frac{64 + 52}{2} - \theta_{0} \right\rbrack \Rightarrow 1.2 = K\lbrack 58 - \theta_{0}\rbrack\ \ \ ...(ii)$
On solving equation (i) and (ii), $\theta_{0} = 49℃$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.