The absolute temperatures of two black bodies are $2000\ K$ and $3000\ K$ respectively. The ratio of wavelengths corresponding to maximum emission of radiation by them will be

Question

Dr. Abubacker · Accepted Answer

(b) $\lambda_{m}T = \lambda_{m}^{'}T^{'} \Rightarrow \frac{\lambda_{m}}{\lambda_{m}^{'}} = \frac{T^{'}}{T} = \frac{3000}{2000} = \frac{3}{2}$

Q. The absolute temperatures of two black bodies are $2000\ K$ and $3000\ K$ respectively. The ratio of wavelengths corresponding to maximum emission of radiation by them will be

Explanation

Reviewed by Dr. Abubacker

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