Q. A black body is heated from $27℃$ to $127℃$. The ratio of their energies of radiations emitted will be
A) 3 : 4
B) 9 : 16
C) 27 : 64
D) 81 : 256
Explanation
(d) $\frac{Q_{1}}{Q_{2}} = \frac{T_{1}^{4}}{T_{2}^{4}} = \left( \frac{273 + 27}{273 + 127} \right)^{4} = \left( \frac{300}{400} \right)^{4} = \frac{81}{256}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.