A black body at a temperature of $127℃$ radiates heat at the rate of $1\ cal/cm^{2} imes sec$. At a temperature of $527℃$ the rate of heat radiation from the body in $(cal/cm^{2} imes sec)$ will be

Question

A black body at a temperature of $127℃$ radiates heat at the rate of $1\ cal/cm^{2} 	imes sec$. At a temperature of $527℃$ the rate of heat radiation from the body in $(cal/cm^{2} 	imes sec)$ will be

Dr. Abubacker · Accepted Answer

(a) $\frac{Q_{2}}{Q_{1}} = \frac{T_{2}^{4}}{T_{1}^{4}} = \left( \frac{273 + 527}{273 + 127} ight)^{4} = \left( \frac{800}{400} ight)^{4} \Rightarrow Q_{2} = 16\frac{cal}{cm^{2} 	imes s}$

Q. A black body at a temperature of $127℃$ radiates heat at the rate of $1\ cal/cm^{2} \times sec$. At a temperature of $527℃$ the rate of heat radiation from the body in $(cal/cm^{2} \times sec)$ will be

Explanation

Reviewed by Dr. Abubacker

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