Q. On a new scale of temperature (which is linear) and called the $W$ scale, the freezing and boiling points of water are $39^{o}\ W$ and $239^{o}W$ respectively. What will be the temperature on the new scale, corresponding to a temperature of $39℃$ on the Celsius scale
A) $200^{o}W$
B) $139^{o}W$
C) $78^{o}W$
D) $117^{o}W$
Explanation
(d) $\frac{X - LFP}{UFP - LFP} = constant$
Where $X =$ Any given temperature on that scale
$L.F.P. =$ Lower fixed point (Freezing point)
$U.F.P.\ =$ Upper fixed point (Boiling point)
$\frac{W - 39}{239 - 39} = \frac{39 - 0}{100 - 0}$
$\Rightarrow \frac{W - 39}{200} = \frac{39}{100} \Rightarrow W = 78 + 39 \Rightarrow W = 117^{o}W$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.