Q. The ratio of energy of emitted radiation of a black body at $27℃$ and $927℃$ is
A) 1 : 4
B) 1 : 16
C) 1 : 64
D) 1 : 256
Explanation
(d) $\frac{Q_{1}}{Q_{2}} = \left( \frac{T_{1}}{T_{2}} \right)^{4} = \left( \frac{273 + 27}{273 + 927} \right)^{4} = \left( \frac{1}{4} \right)^{4} = \frac{1}{256}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.