Q. A rectangular block is heated from 0$℃\ $to 100$℃$. The percentage increase in its length is 0.2%. What is the percentage increase in its volume?
A) 0.6%
B) 0.10%
C) 0.2%
D) 0.4%
Explanation
(a) As $V = L^{3}$
$\therefore\ \frac{\mathrm{\Delta}V \times 100}{V} = 3\frac{\mathrm{\Delta}L \times 100}{L}$
= 3$\times 0.2\% = 0.6\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.