Q. $4200\ J$ of work is required for
A) Increasing the temperature of $10\ gm$ of water through $10℃$
B) Increasing the temperature of $100\ gm$ of water through $10℃$
C) Increasing the temperature of $1\ kg$ of water through $10℃$
D) Increasing the temperature of $10\ kg\ $ of water through $10℃$
Explanation
(b) Work done to raise the temperature of $100\ gm$ water through $10℃$ is
$W = JQ = 4.2 \times \left( 100 \times 10^{- 3} \times 1000 \times 10 \right) = 4200\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.