Q. In a steady state of thermal conduction, temperature of the ends $A$ and $B$ of a $20\ cm$ long rod are $100℃$ and $0℃$ respectively. What will be the temperature of the rod at a point at a distance of $6\ cm$ from the end $A$ of the rod
A) $- 30℃$
B) $70℃$
C) $5℃$
D) None of the above
Explanation
(b) In steady state, temperature gradient = constant
$\Rightarrow \frac{(\theta_{A} - \theta_{x})}{6} = \frac{(\theta_{A} - \theta_{B})}{20} \Rightarrow \left( 100 - \theta_{x} \right) = \frac{6}{20} \times (100 - 0)$
$\Rightarrow \theta_{x} = 70℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.