Q. Calculate the amount of heat (in calories) required to convert $5\ g$ of ice at $0℃$ to steam at $100℃$
A) $3100\ cal$
B) $3200\ cal$
C) $3600\ cal$
D) $4200\ cal$
Explanation
(c) Ice $(0℃)$ converts into steam $(100℃)$ in following three steps.
Total heat required $Q = Q_{1} + Q_{2} + Q_{3}$
$= 5 \times 80 + 5 \times 1 \times (100 - 0) + 5 \times 540 = 3600\ cal$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.